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Two neutron decay from the 21+ state of 6He

Yuma Kikuchi, Takuma Matsumoto, Kosho Minomo, and Kazuyuki Ogata
Phys. Rev. C 88, 021602(R) – Published 30 August 2013

Abstract

Decay mode of the 21+ resonant state of 6He populated by the 6He breakup reaction by 12C at 240 MeV/nucleon is investigated. The continuum-discretized coupled-channels method is adopted to describe the formation of the 21+ state, whereas its decay is described by the complex-scaled solutions of the Lippmann-Schwinger equation. From analysis of invariant mass spectra with respect to the α-n and n-n subsystems, coexistence of two decay modes is found. One is the simultaneous decay of two neutrons correlating with each other and the other is the emission of two neutrons to the opposite directions. The latter is found to be free from the final-state interaction and suggests existence of a dineutron in the 21+ state of 6He.

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  • Received 29 July 2013

DOI:https://doi.org/10.1103/PhysRevC.88.021602

©2013 American Physical Society

Authors & Affiliations

Yuma Kikuchi1,*, Takuma Matsumoto2, Kosho Minomo2, and Kazuyuki Ogata1

  • 1Research Center for Nuclear Physics, Osaka University, Ibaraki, Osaka 567-0047, Japan
  • 2Department of Physics, Kyushu University, Fukuoka 812-8581, Japan

  • *yuma@rcnp.osaka-u.ac.jp

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Issue

Vol. 88, Iss. 2 — August 2013

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