Abstract
In contrast to normal Fermi liquids, where the momentum distribution n(k) has a discontinuous jump at k=, in Luttinger liquids a power-law singularity appears in n(k). It was argued that this singularity shows up not only at but at 3,5, . . . as well, and the anomaly exponent has been detemined for the one-dimensional Hubbard model using numerical methods or assuming conformal invariance. We present an exact calculation of the anomaly exponent for the Tomonaga-Luttinger model and compare it with the results for the Hubbard model.
- Received 26 July 1991
DOI:https://doi.org/10.1103/PhysRevB.44.12690
©1991 American Physical Society