Hubbard model with one hole: Ground-state properties

E. Dagotto, A. Moreo, and T. Barnes
Phys. Rev. B 40, 6721 – Published 1 October 1989
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Abstract

The ground state of the two-dimensional Hubbard model on a square lattice is studied in the large-U limit in a half-filled band with a dynamical hole. For a 4×4 lattice with hopping t=1 and coupling J<Jc≊0.075, the ground state has zero momentum (k) and spin 15/2 (ferromagnetic background). For J≥Jc the ground state is degenerate with nonzero k and spin 1/2, in agreement with recent variational calculations. The nonzero k of the ground state comes from a nontrivial phase in the overlap of the spin states before and after a hole move. For small lattices we show that the effective Hamiltonian of the hole is that of a particle moving in a magnetic field. We also find that many of the features of the weak-coupling region carry over continuously to the strong-coupling region.

  • Received 26 May 1989

DOI:https://doi.org/10.1103/PhysRevB.40.6721

©1989 American Physical Society

Authors & Affiliations

E. Dagotto

  • Institute for Theoretical Physics, University of California at Santa Barbara, Santa Barbara, California 93106

A. Moreo

  • Department of Physics, University of California at Santa Barbara, Santa Barbara, California 93106

T. Barnes

  • Department of Physics, University of Toronto, Toronto, Ontario, Canada M5S 1A7

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Vol. 40, Iss. 10 — 1 October 1989

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